What is the valid host range for the subnet where the IP address 192.168.168.188 255.255.255.192 resides?

To determine the valid host range for the subnet where the IP address 192.168.168.188 with a subnet mask of 255.255.255.192 resides, we must first understand the implications of the subnet mask.

The subnet mask 255.255.255.192 can also be expressed in CIDR notation as /26. This means that there are 64 possible IP addresses in this subnet (2^(32-26) = 64), since the mask allocates 26 bits for the network and leaves 6 bits for host addresses.

Next, we can find the subnet boundary for this address. The subnet spans from 192.168.168.128 to 192.168.168.191. The range of valid host IP addresses in a subnet excludes the network address (the first address, which is used to identify the subnet itself) and the broadcast address (the last address, used for broadcasting to all hosts in the subnet).

Therefore, the valid hosts for this subnet are those between 192.168.168.129 and 192.168.168.190. The first valid host address is 192.168.168.129, and the last valid host address is 192.168